The 1836 United States presidential election in Pennsylvania took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.

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1836 United States presidential election in Pennsylvania

← 1832 November 3 – December 7, 1836 1840 →

Nominee Martin Van Buren William Henry Harrison Party Democratic Whig Home state New York Ohio Running mate Richard Johnson Francis Granger Electoral vote 30 0 Popular vote 91,457 87,235 Percentage 51.18% 48.82%

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

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Pennsylvania voted for the Democratic candidate, Martin Van Buren, over the Whig candidate, William Henry Harrison. Van Buren won Pennsylvania by a narrow margin of 2.36%. The result would ultimately prove decisive in Van Buren's victory; had Harrison won the state, then Van Buren would not have achieved a majority in the Electoral College, meaning that the election would have been decided in the House of Representatives.

• List of United States presidential elections in Pennsylvania