The 1852 United States presidential election in Massachusetts took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose 13 representatives, or electors to the Electoral College, who voted for President and Vice President.

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1852 United States presidential election in Massachusetts

← 1848 November 2, 1852 1856 →
Turnout	57.8%[1] 6.8 pp
Nominee Winfield Scott Franklin Pierce John P. Hale Party Whig Democratic Free Soil Home state New Jersey New Hampshire New Hampshire Running mate William A. Graham William R. King George W. Julian Electoral vote 13 0 0 Popular vote 52,683 44,569 28,023 Percentage 41.45% 35.07% 22.05%
County Results Scott   40-50%   50-60%   60-70% Pierce   50-60%
President before election Millard Fillmore Whig Elected President Franklin Pierce Democratic

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Massachusetts voted for the Whig Party candidate, Winfield Scott, over the Democratic candidate, Franklin Pierce. Scott won the state by a narrow margin of 6.38%.

Massachusetts was one of the four states to vote for Scott. The other three were Kentucky, Tennessee and Vermont. Free Soil Party candidate John P. Hale won 22.05% of the vote in the state, making Massachusetts his strongest state.^[2]

Daniel Webster died 9 days before the election of a cerebral hemorrhage on October 24, 1852. This caused many Union and Native American state parties to remove him and his running mate Charles Jones Jenkins from their slates of electors and was replaced by Jacob Broom and Reynell Coates. The Webster-Jenkins Union ticket, however, remained on the ballot in both Massachusetts and Georgia. As of 2020, this election marks only the first of three times (after 1972 and 1980) that Massachusetts has not voted for the same candidate as neighboring Rhode Island.

• United States presidential elections in Massachusetts