1856_United_States_presidential_election_in_Rhode_Island

1856 United States presidential election in Rhode Island

1856 United States presidential election in Rhode Island

Election in Rhode Island

The 1856 United States presidential election in Rhode Island took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1856 United States presidential election
Quick Facts Nominee, Party ...

Rhode Island voted for the Republican candidate, John C. Frémont, over the Democratic candidate, James Buchanan, and the Know Nothing candidate, Millard Fillmore. Frémont won the state by a margin of 24.15%.

With 57.85% of the popular vote, Rhode Island proved to be Frémont's fourth strongest state in the 1856 election after Vermont, Massachusetts and Maine.[1]

Results

More information Party, Candidate ...

See also

References

  1. [1]
    "1856 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. [2]
    "1856 Presidential General Election Results - Rhode Island".


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