The 1876 United States presidential election in Rhode Island took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

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1876 United States presidential election in Rhode Island

← 1872 November 7, 1876 1880 →

Nominee Rutherford B. Hayes Samuel J. Tilden Party Republican Democratic Home state Ohio New York Running mate William A. Wheeler Thomas A. Hendricks Electoral vote 4 0 Popular vote 15,787 10,712 Percentage 59.29% 40.23%

County Results Hayes   50-60%   60-70%

President before election Ulysses S. Grant Republican Elected President Rutherford B. Hayes Republican

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Rhode Island voted for the Republican nominee, Rutherford B. Hayes, over the Democratic nominee, Samuel J. Tilden. Hayes won the state by a margin of 19.06%.

With 59.29% of the popular vote, Rhode Island would be Hayes' fourth strongest victory in terms of percentage in the popular vote after Vermont, Nebraska and Kansas.^[1]

This was the only election between 1860 and 1888 where the Democratic candidate earned more than 40% statewide, as well as the only election in the same period where the Democratic candidate earned more than 40% in at least one Rhode Island county.

• United States presidential elections in Rhode Island