1880_United_States_presidential_election_in_Rhode_Island

1880 United States presidential election in Rhode Island

1880 United States presidential election in Rhode Island

Election in Rhode Island

The 1880 United States presidential election in Rhode Island took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1880 United States presidential election
Quick Facts Nominee, Party ...

Rhode Island voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a margin of 25.37%.

With 62.24% of the popular vote, Rhode Island would be Garfield's fourth strongest victory in terms of percentage in the popular vote after Vermont, Nebraska and Minnesota.[1]

Results

More information Party, Candidate ...

See also

References

  1. [1]
    "1880 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. [2]
    "1880 Presidential General Election Results - Rhode Island". Dave Leip's Atlas of U.S. Presidential Elections.


Stub icon 1 Stub icon 2

This Rhode Island elections-related article is a stub. You can help Wikipedia by expanding it.
Share this article:

This article uses material from the Wikipedia article 1880_United_States_presidential_election_in_Rhode_Island, and is written by contributors. Text is available under a CC BY-SA 4.0 International License; additional terms may apply. Images, videos and audio are available under their respective licenses.