1884_United_States_presidential_election_in_Rhode_Island

1884 United States presidential election in Rhode Island

1884 United States presidential election in Rhode Island

Election in Rhode Island

The 1884 United States presidential election in Rhode Island took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1884 United States presidential election
Quick Facts Nominee, Party ...

Rhode Island voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a margin of 20.26%.

With 58.07% of the popular vote, Rhode Island would prove to be Blaine's fourth strongest victory in terms of percentage in the popular vote after Vermont, Minnesota and Kansas.[1]

Results

More information Party, Candidate ...

See also

References

  1. [1]
    "1884 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. [2]
    "1884 Presidential General Election Results - Rhode Island".


Stub icon 1 Stub icon 2

This Rhode Island elections-related article is a stub. You can help Wikipedia by expanding it.
Share this article:

This article uses material from the Wikipedia article 1884_United_States_presidential_election_in_Rhode_Island, and is written by contributors. Text is available under a CC BY-SA 4.0 International License; additional terms may apply. Images, videos and audio are available under their respective licenses.