1896_United_States_presidential_election_in_Maryland

1896 United States presidential election in Maryland

1896 United States presidential election in Maryland

U.S. presidential election in Maryland


The 1896 United States presidential election in Maryland took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. States voters chose eight electors to the Electoral College, which selected the president and vice president.

Quick Facts Nominee, Party ...

Maryland was won by the Republican nominees, former Ohio Governor William McKinley and his running mate Garret Hobart of New Jersey. They defeated the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan and his running mate Arthur Sewall. McKinley won the state by a margin of 13.11%.

This was the first time that a Republican presidential candidate won Maryland since Abraham Lincoln in 1864 and the Democrats would not win the state's popular vote until Woodrow Wilson in 1912.

In this election, Maryland voted 8.8% more Republican than the nation at-large.[1]

Bryan would lose Maryland to McKinley again four years later. In 1908, he would lose the popular vote to William Howard Taft but would win the electoral vote.

Results

More information Party, Candidate ...

Results by county

More information County, William McKinley Republican ...

Counties that flipped from Democratic to Republican

See also


References

  1. "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved June 22, 2023.
  2. Géoelections; Popular Vote at the Presidential Election for 1896 (.xlsx file for €30 including full minor party figures)

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