1929_U.S._National_Championships_–_Women's_singles

1929 U.S. National Championships – Women's singles

1929 U.S. National Championships – Women's singles

1929 tennis event results


First-seeded Helen Wills defeated Phoebe Holcroft Watson 6–4, 6–2 in the final to win the women's singles tennis title at the 1929 U.S. National Championships. It was her sixth U.S. National singles title and her third in a row.[1][2][3]

Quick Facts Women's singles, Final ...

Seeds

The tournament used a list of eight U.S. players and six foreign players for seeding the women's singles event. Helen Wills is the champion; others show in brackets the round in which they were eliminated.[4]

Draw

Final eight

Quarterfinals Semifinals Finals
               
1 United States Helen Wills 6 6
(3) United Kingdom Peggy Saunders Michell 0 1
1 United States Helen Wills 6 6
4 United States Molla Bjurstedt Mallory 0 0
4 United States Molla Bjurstedt Mallory 6 6
(1) United Kingdom Betty Nuthall 3 3
1 United States Helen Wills 6 6
(2) United Kingdom Phoebe Holcroft Watson 4 2
3 United States Edith Cross 6 1 3
(2) United Kingdom Phoebe Holcroft Watson 2 6 6
(2) United Kingdom Phoebe Holcroft Watson 6 3 6
2 United States Helen Jacobs 1 6 1
6 United States Mary Greef 2 2
2 United States Helen Jacobs 6 6

References

  1. Collins, Bud (2010). The Bud Collins History of Tennis (2nd ed.). [New York City]: New Chapter Press. p. 469. ISBN 978-0942257700.
  2. "Helen Wills Takes Sixth National Title". Chicago Tribune. AP. August 25, 1929. p. 1, Part 2.
Preceded by Grand Slam women's singles Succeeded by

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