1939_U.S._National_Championships_–_Women's_Singles

1939 U.S. National Championships – Women's singles

1939 U.S. National Championships – Women's singles

1939 tennis event results

First-seeded Alice Marble defeated second-seeded Helen Jacobs 6–0, 8–10, 6–4 in the final to win the women's singles tennis title at the 1939 U.S. National Championships. The tournament was played on outdoor grass courts and held from September 7, through September 17, 1939 at the West Side Tennis Club in Forest Hills, Queens, New York.[1][2]

Quick Facts Women's singles, Final ...

The draw consisted of 64 players of which eight were seeded.

Seeds

The eight seeded U.S. players are listed below. Alice Marble is the champion; others show in brackets the round in which they were eliminated.

  1. United States Alice Marble (champion)
  2. United States Helen Jacobs (finalist)
  3. United States Sarah Fabyan (quarterfinals)
  4. United States Dorothy Bundy (quarterfinals)
  5. United States Gracyn Wheeler (first round)
  6. United States Helen Bernhard (third round)
  7. United States Dorothy Workman (third round)
  8. United States Virginia Wolfenden (semifinals)

Draw

Final eight

Quarterfinals Semifinals Finals
               
2 United States Helen Jacobs 2 6 6
United Kingdom Valerie Scott 6 2 3
2 United States Helen Jacobs 7 6
United Kingdom Kay Stammers 5 0
3 United States Sarah Fabyan 6 3 3
United Kingdom Kay Stammers 1 6 6
2 United States Helen Jacobs 0 10 4
1 United States Alice Marble 6 8 6
1 United States Alice Marble 6 6 6
United Kingdom Mary Hardwick 3 8 2
1 United States Alice Marble 6 6
8 United States Virginia Wolfenden 0 1
4 United States Dorothy Bundy 6 1 2
8 United States Virginia Wolfenden 2 6 6

References

  1. [1]
    Collins, Bud (2016). The Bud Collins History of Tennis (3rd ed.). New York: New Chapter Press. p. 498. ISBN 978-1-937559-38-0.
  2. [2]
    "Rigs defeats Van Horn". The Advocate. Tasmania, Australia. September 19, 1939. p. 3 – via National Library of Australia.
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