1948_United_States_presidential_election_in_Rhode_Island

1948 United States presidential election in Rhode Island

1948 United States presidential election in Rhode Island

Election in Rhode Island


The 1948 United States presidential election in Rhode Island took place on November 2, 1948, as part of the 1948 United States presidential election. State voters chose four electors to the Electoral College, which selected the president and vice president.

Quick Facts Nominee, Party ...

Rhode Island was won by Democratic candidate, incumbent President Harry S. Truman of Missouri, over the Republican candidate, Governor Thomas E. Dewey of New York. Truman ran with Senator Alben W. Barkley of Kentucky as his running mate, while Dewey ran with Governor Earl Warren of California as his running mate.

Truman won Rhode Island by a margin of 16.15%.

Results

More information Party, Candidate ...

By county

More information County, Harry Truman Democratic ...

See also


References

  1. "1948 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved December 23, 2013.
  2. "RI.gov: Election Results". www.ri.gov. Retrieved February 15, 2024.



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