1976_United_States_presidential_election_in_Rhode_Island

1976 United States presidential election in Rhode Island

1976 United States presidential election in Rhode Island

Election in Rhode Island


The 1976 United States presidential election in Rhode Island took place on November 2, 1976, as part of the 1976 United States presidential election. Voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.

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Rhode Island was won by Jimmy Carter (DGeorgia), with 55.36% of the popular vote. Carter defeated incumbent President Gerald Ford (RMichigan), who finished with 44.08% of the popular vote. No third-party candidate received any votes.

Jimmy Carter went on to become the 39th president of the United States.[2]

Results

More information Party, Candidate ...

By county

More information County, Carter % ...

Counties flipped from Republican to Democratic

See also


References

  1. This figure is calculated by dividing the total number of votes cast in 1976 (416,583) by an estimate of the number of registered voters in Rhode Island in 1976 (544,992). See "General Election November 2, 1976". Rhode Island Board of Elections. Retrieved February 6, 2018.
  2. "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved February 11, 2024.
  3. "RI.gov: Election Results". www.ri.gov. Retrieved February 11, 2024.



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