1992_United_States_presidential_election_in_Rhode_Island

1992 United States presidential election in Rhode Island

1992 United States presidential election in Rhode Island

Election in Rhode Island


The 1992 United States presidential election in Rhode Island took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Quick Facts Turnout, Nominee ...

Rhode Island was won by Governor Bill Clinton (D-Arkansas) with 47.04% of the popular vote over incumbent President George H. W. Bush (R-Texas) with 29.02%. Businessman Ross Perot (I-Texas) finished in third, with 23.16% of the popular vote.[2] Clinton ultimately won the national vote, defeating incumbent President Bush.[3]

Results

More information Party, Candidate ...

By county

More information County, Bill Clinton Democratic ...

See also


References

  1. This figure is calculated by dividing the total number of votes cast in 1992 (424,818) by an estimate of the number of registered voters in Rhode Island in 1992 (554,664). See "Voter Turnout, 1992". Rhode Island Board of Elections. Retrieved February 6, 2018.
  2. "1992 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved June 9, 2012.
  3. "1992 Presidential General Election Results". U.S. Election Atlas. Retrieved June 9, 2012.

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