2018 China Open (snooker)

The 2018 Fuhua Group China Open was a professional ranking snooker tournament, taking place from 2–8 April 2018 in Beijing, China.[1] It was the nineteenth and penultimate ranking event of the 2017/2018 season.

China Open
Tournament information
Dates2–8 April 2018
VenueOlympic Sports Center Gymnasium
CityBeijing
CountryChina
Organisation(s)WPBSA
FormatRanking event
Total prize fund£1,000,000
Winner's share£225,000
Highest break Ronnie O'Sullivan (147)
Stuart Bingham (147)
Final
Champion Mark Selby
Runner-up Barry Hawkins
Score11–3
2017
2019

Defending champion Mark Selby retained his title with an 11–3 final win against Barry Hawkins.[2] By winning this tournament, Selby ensured that he will end a seventh consecutive season as world number one, regardless of his result in the 2018 World Championship.

Ronnie O'Sullivan made his 14th maximum break in professional competition in the 5th frame of his last 64 match against Elliot Slessor.[3] The following day Stuart Bingham made his fourth maximum break in professional competition in the 7th frame of his last 32 match against Ricky Walden.[4] These were the 137th and 138th official maximum breaks in professional competition. It was only the second time that two 147s were made at the main stage of a professional ranking event, the first time being at the 2008 World Championship.