Sémelay


Sémelay (French pronunciation: [semlɛ]) is a commune in the Nièvre department in central France. The town of Sémelay belongs to the canton of Luzy and the district of Château-Chinon(Ville).[3]

Sémelay
The church in Sémelay
Location of Sémelay
Sémelay
Sémelay
Coordinates: 46°51′09″N 3°51′07″E
CountryFrance
RegionBourgogne-Franche-Comté
DepartmentNièvre
ArrondissementChâteau-Chinon
CantonLuzy
Government
  Mayor (20202026) Guy Laffaye[1]
Area
1
33.53 km2 (12.95 sq mi)
Population
 (Jan. 2018)[2]
227
  Density6.8/km2 (18/sq mi)
Time zoneUTC+01:00 (CET)
  Summer (DST)UTC+02:00 (CEST)
INSEE/Postal code
58276 /58360
Elevation227–530 m (745–1,739 ft)
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries.

Geography


The river Alène flows westward through the southern part of commune.

The town's surface is 33.4 km². It is situated at an altitude of about 292 meters. It Is situated "at altitude of about 292 year meters.[4]

Demographics


At the 1999 census, the population was 279. On 1 January 2004, the estimate was 268.

See also


References


  1. "Répertoire national des élus: les maires". data.gouv.fr, Plateforme ouverte des données publiques françaises (in French). 2 December 2020. Retrieved 7 December 2020.
  2. "Populations légales 2018". INSEE. 28 December 2020.
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