Sphericity is a measure of how closely the shape of an object resembles that of a perfect sphere . For example, the sphericity of the balls inside a ball bearing determines the quality of the bearing, such as the load it can bear or the speed at which it can turn without failing. Sphericity is a specific example of a compactness measure of a shape . Defined by Wadell in 1935,[1] the sphericity, $\Psi$ , of a particle is the ratio of the surface area of a sphere with the same volume as the given particle to the surface area of the particle:

$\Psi ={\frac {\pi ^{\frac {1}{3}}(6V_{p})^{\frac {2}{3}}}{A_{p}}}$

Schematic representation of difference in grain shape. Two parameters are shown: sphericity (vertical) and rounding (horizontal).
where $V_{p}$ is volume of the particle and $A_{p}$ is the surface area of the particle. The sphericity of a sphere is unity by definition and, by the isoperimetric inequality , any particle which is not a sphere will have sphericity less than 1.

Sphericity applies in three dimensions ; its analogue in two dimensions , such as the cross sectional circles along a cylindrical object such as a shaft , is called roundness .

Ellipsoidal objects
The sphericity, $\Psi$ , of an oblate spheroid (similar to the shape of the planet Earth ) is:

$\Psi ={\frac {\pi ^{\frac {1}{3}}(6V_{p})^{\frac {2}{3}}}{A_{p}}}={\frac {2{\sqrt[{3}]{ab^{2}}}}{a+{\frac {b^{2}}{\sqrt {a^{2}-b^{2}}}}\ln {\left({\frac {a+{\sqrt {a^{2}-b^{2}}}}{b}}\right)}}},$
where a and b are the semi-major and semi-minor axes respectively.

Derivation
Hakon Wadell defined sphericity as the surface area of a
sphere of the same volume as the particle divided by the actual surface area of the particle.

First we need to write surface area of the sphere, $A_{s}$ in terms of the volume of the particle, $V_{p}$

$A_{s}^{3}=\left(4\pi r^{2}\right)^{3}=4^{3}\pi ^{3}r^{6}=4\pi \left(4^{2}\pi ^{2}r^{6}\right)=4\pi \cdot 3^{2}\left({\frac {4^{2}\pi ^{2}}{3^{2}}}r^{6}\right)=36\pi \left({\frac {4\pi }{3}}r^{3}\right)^{2}=36\,\pi V_{p}^{2}$
therefore

$A_{s}=\left(36\,\pi V_{p}^{2}\right)^{\frac {1}{3}}=36^{\frac {1}{3}}\pi ^{\frac {1}{3}}V_{p}^{\frac {2}{3}}=6^{\frac {2}{3}}\pi ^{\frac {1}{3}}V_{p}^{\frac {2}{3}}=\pi ^{\frac {1}{3}}\left(6V_{p}\right)^{\frac {2}{3}}$
hence we define $\Psi$ as:

$\Psi ={\frac {A_{s}}{A_{p}}}={\frac {\pi ^{\frac {1}{3}}\left(6V_{p}\right)^{\frac {2}{3}}}{A_{p}}}$
Sphericity of common objects
Name
Picture
Volume
Surface Area
Sphericity
Platonic Solids
tetrahedron
${\frac {\sqrt {2}}{12}}\,s^{3}$ ${\sqrt {3}}\,s^{2}$ $\left({\frac {\pi }{6{\sqrt {3}}}}\right)^{\frac {1}{3}}\approx 0.671$
cube (hexahedron)
$\,s^{3}$ $6\,s^{2}$
$\left({\frac {\pi }{6}}\right)^{\frac {1}{3}}\approx 0.806$

octahedron
${\frac {1}{3}}{\sqrt {2}}\,s^{3}$ $2{\sqrt {3}}\,s^{2}$
$\left({\frac {\pi }{3{\sqrt {3}}}}\right)^{\frac {1}{3}}\approx 0.846$

dodecahedron
${\frac {1}{4}}\left(15+7{\sqrt {5}}\right)\,s^{3}$ $3{\sqrt {25+10{\sqrt {5}}}}\,s^{2}$
$\left({\frac {\left(15+7{\sqrt {5}}\right)^{2}\pi }{12\left(25+10{\sqrt {5}}\right)^{\frac {3}{2}}}}\right)^{\frac {1}{3}}\approx 0.910$

icosahedron
${\frac {5}{12}}\left(3+{\sqrt {5}}\right)\,s^{3}$ $5{\sqrt {3}}\,s^{2}$ $\left({\frac {\left(3+{\sqrt {5}}\right)^{2}\pi }{60{\sqrt {3}}}}\right)^{\frac {1}{3}}\approx 0.939$
Round Shapes
ideal cone $(h=2{\sqrt {2}}r)$
${\frac {1}{3}}\pi \,r^{2}h$
$={\frac {2{\sqrt {2}}}{3}}\pi \,r^{3}$

$\pi \,r(r+{\sqrt {r^{2}+h^{2}}})$
$=4\pi \,r^{2}$

$\left({\frac {1}{2}}\right)^{\frac {1}{3}}\approx 0.794$
hemisphere (half sphere)
${\frac {2}{3}}\pi \,r^{3}$ $3\pi \,r^{2}$
$\left({\frac {16}{27}}\right)^{\frac {1}{3}}\approx 0.840$

ideal cylinder $(h=2\,r)$
$\pi r^{2}h=2\pi \,r^{3}$ $2\pi r(r+h)=6\pi \,r^{2}$
$\left({\frac {2}{3}}\right)^{\frac {1}{3}}\approx 0.874$

ideal torus $(R=r)$
$2\pi ^{2}Rr^{2}=2\pi ^{2}\,r^{3}$ $4\pi ^{2}Rr=4\pi ^{2}\,r^{2}$
$\left({\frac {9}{4\pi }}\right)^{\frac {1}{3}}\approx 0.894$

sphere
${\frac {4}{3}}\pi r^{3}$ $4\pi \,r^{2}$
$1\,$

Other Shapes
rhombic triacontahedron
$4{\sqrt {5+2{\sqrt {5}}}}\,s^{3}$ $12{\sqrt {5}}\,s^{2}$ ${\frac {\pi ^{\frac {1}{3}}\left(24{\sqrt {5+2{\sqrt {5}}}}\,s^{3}\right)^{\frac {2}{3}}}{12{\sqrt {5}}\,s^{2}}}\approx 0.9609$
disdyakis triacontahedron
${\frac {180}{11}}{\sqrt {179-24{\sqrt {5}}}}$ ${\frac {180}{11}}\left(5+4{\sqrt {5}}\right)$ ${\frac {\left(\left(5+4{\sqrt {5}}\right)^{2}{\frac {11\pi }{5}}\right)^{\frac {1}{3}}}{\sqrt {179-24{\sqrt {5}}}}}\approx 0.9857$

See also
References