The 2000 United States presidential election in Rhode Island took place on November 7, 2000, and was part of the 2000 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

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2000 United States presidential election in Rhode Island

← 1996 November 7, 2000 2004 →
Turnout	61.4%[1] 3.4 pp
Nominee Al Gore George W. Bush Ralph Nader Party Democratic Republican Green Home state Tennessee Texas Connecticut Running mate Joe Lieberman Dick Cheney Winona LaDuke Electoral vote 4 0 0 Popular vote 249,508 130,555 25,052 Percentage 60.99% 31.91% 6.12%
County Results Municipality Results Gore   40–50%   50–60%   60–70%   70–80% Bush   40–50%
President before election Bill Clinton Democratic Elected President George W. Bush Republican

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Rhode Island voted for the Democratic Party's candidate, then Vice President Al Gore of Tennessee, over the Republican Party's candidate, Governor George W. Bush of Texas. Gore ran with Senator Joe Lieberman of Connecticut as his running mate, while Bush ran with former Secretary of Defense Dick Cheney as his running mate.

Rhode Island is one of the most reliably Democratic states in the country. This state was Democrat Al Gore's best performance in the 2000 presidential election, where he won with over 60% of the vote. Gore won all five of the Ocean State's counties and won all but two townships. Ralph Nader, running a high-profile campaign on behalf of the Green Party with Winona LaDuke as his running mate, took 6.12% of the popular vote in the state, making Rhode Island his fourth best showing in the 2000 election after Alaska, Vermont and neighboring Massachusetts.^[2][3]

• United States presidential elections in Rhode Island