1912_United_States_presidential_election_in_Arkansas

1912 United States presidential election in Arkansas

1912 United States presidential election in Arkansas

Election in Arkansas


The 1912 United States presidential election in Arkansas took place on November 5, 1912, as part of the 1912 United States presidential election. Voters chose nine representatives, or electors, to the Electoral College, who voted for president and vice president.

Quick Facts Nominee, Party ...

Arkansas was won by Princeton University President Woodrow Wilson (DVirginia), running with governor of Indiana Thomas R. Marshall, with 55.01 percent of the popular vote, against the 27th president of the United States William Howard Taft (ROhio), running with Columbia University President Nicholas Murray Butler, with 20.45 percent, the 26th president of the United States Theodore Roosevelt (PNew York), running with governor of California Hiram Johnson, with 17.30 percent, and the five-time candidate of the Socialist Party of America for President of the United States Eugene V. Debs (SIndiana), running with the first Socialist mayor of a major city in the United States Emil Seidel, with 6.52 percent.[1]

Results

More information Party, Candidate ...

Results by county

More information County, Thomas Woodrow Wilson Democratic ...

See also

Notes

  1. In this county where Roosevelt ran second ahead of Taft, the margins given are those between Wilson and Roosevelt.
  2. In this county where Debs ran second ahead of Taft and of Roosevelt, the margin given is that between Wilson and Debs.
  3. Different sources reverse the Republican vote totals for Sebastian and Searcy Counties.
    In contrast to Deve Leip’s Atlas, Géoelections has 389 Taft votes in Searcy County and 514 in Sebastian County, which would have given Searcy County to Wilson and the Democratic Party

References

  1. "1912 Presidential Election Results – Arkansas". Dave Leip’s U.S. Election Atlas.

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