1940_United_States_presidential_election_in_Nevada

1940 United States presidential election in Nevada

1940 United States presidential election in Nevada

Election in Nevada


The 1940 United States presidential election in Nevada took place on November 5, 1940, as part of the 1940 United States presidential election. State voters chose three[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Quick Facts All 3 Nevada votes to the Electoral College, Nominee ...

Nevada was won by incumbent President Franklin D. Roosevelt (DNew York), running with Secretary Henry A. Wallace, with 60.08% of the popular vote, against Wendell Willkie (RNew York), running with Minority Leader Charles L. McNary, with 39.92% of the popular vote.[3][4] As of the 2020 presidential election, this is the last election in which Lyon County and Churchill County voted for a Democratic presidential candidate.[5]

Results

More information Party, Candidate ...

Results by county

More information County, Franklin Delano Roosevelt Democratic ...

See also


References

  1. "United States Presidential election of 1940 – Encyclopædia Britannica". Retrieved August 21, 2018.
  2. Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016
  3. Scammon, Richard M. (compiler); America at the Polls: A Handbook of Presidential Election Statistics 1920-1964; p. 290 ISBN 0405077114



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