The 1836 United States presidential election in Alabama took place between November 3 and December 7, 1836, as part of the 1836 presidential election. Voters chose seven representatives, or electors, to the Electoral College, who voted for President and Vice President.

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1836 United States presidential election in Alabama

← 1832 November 3 – December 7, 1836 1840 →

Nominee Martin Van Buren Hugh White Party Democratic Whig Home state New York Tennessee Running mate Richard Johnson John Tyler Electoral vote 7 0 Popular vote 20,638 16,658 Percentage 55.34% 44.66%

County Results Van Buren   50-60%   60-70%   70–80%   80–90%   90-100% White   50-60%   60-70%   70–80%   80–90% Unknown/No Vote

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

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Alabama voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Alabama by a margin of 10.68%.

• United States presidential elections in Alabama