1836_United_States_presidential_election_in_Rhode_Island

1836 United States presidential election in Rhode Island

1836 United States presidential election in Rhode Island

Election in Rhode Island

The 1836 United States presidential election in Rhode Island took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Main article: 1836 United States presidential election
Quick Facts Nominee, Party ...

Rhode Island voted for Democratic candidate Martin Van Buren over Whig candidate William Henry Harrison. Van Buren won Rhode Island by a narrow margin of 4.48%.

This was the first time that Rhode Island ever voted for a Democratic presidential candidate, and Van Buren's performance would not be bettered by a Democrat in Rhode Island until Franklin D. Roosevelt in 1932.[1]

Results

More information Party, Candidate ...

See also

References

  1. [1]
    "Presidential General Election Results Comparison – Rhode Island". Dave Leip’s U.S. Election Atlas. Retrieved October 25, 2019.
  2. [2]
    "1836 Presidential General Election Results - Rhode Island". Dave Leip’s U.S. Election Atlas. Retrieved December 23, 2013.


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