1838_Rhode_Island_gubernatorial_election

1838 Rhode Island gubernatorial election

1838 Rhode Island gubernatorial election

Rhode Island gubernatorial election


The 1838 Rhode Island gubernatorial election was held on April 18, 1838.[1][2]

Quick Facts Nominee, Party ...

Incumbent Democratic Governor John Brown Francis ran for election to a sixth term but was defeated by Whig nominee William Sprague.

General election

Candidates

Results

More information Party, Candidate ...

References

  1. "The Election". Herald of the times. Newport, R.I. March 29, 1838. p. 2. Retrieved October 19, 2021.
  2. "The Elections". Richmond enquirer. Richmond, Va. April 7, 1838. p. 2. Retrieved October 19, 2021.
  3. "RI Governor, 1838". Our Campaigns. Retrieved October 19, 2021.
  4. Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. p. 76. ISBN 1-56802-396-0.
  5. Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. p. 235. ISBN 978-0-7864-1439-0.
  6. Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Westport, CT: Meckler Books. pp. 270–271. ISBN 0-930466-17-9.
  7. Kallenbach, Joseph E.; Kallenbach, Jessamine S., eds. (1977). American State Governors, 1776-1976. Vol. I. Dobbs Ferry, N.Y.: Oceana Publications, Inc. p. 512. ISBN 0-379-00665-0.
  8. Manual with Rules and Orders for the Use of the General Assembly of the State of Rhode Island, 1888-89. State of Rhode Island manual. Providence: E. L. Freeman & Co., Printers to the State. 1888. p. 101.
  9. "Rhode-Island Legislature". The Rhode-Island Republican. Newport, R.I. May 9, 1838. p. 2. Retrieved October 19, 2021.

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