1844_United_States_presidential_election_in_Rhode_Island

1844 United States presidential election in Rhode Island

1844 United States presidential election in Rhode Island

Election in Rhode Island

The 1844 United States presidential election in Rhode Island took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Main article: 1844 United States presidential election
Quick Facts Nominee, Party ...

Rhode Island voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won Rhode Island by a margin of 19.97%.

With 59.55% of the popular vote, Rhode Island would prove to be Henry Clay's strongest state in the nation.[1]

Results

More information Party, Candidate ...

See also

References

  1. [1]
    "1844 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. [2]
    "1844 Presidential General Election Results - Rhode Island". U.S. Election Atlas. Retrieved December 23, 2013.


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