1860_United_States_presidential_election_in_Indiana

1860 United States presidential election in Indiana

1860 United States presidential election in Indiana

Election in Indiana


The 1860 United States presidential election in Indiana took place on November 6, 1860, as part of the 1860 United States presidential election. Indiana voters chose 13 representatives, or electors, to the Electoral College, who voted for president and vice president.

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Indiana was won by Republican nominee Representative Abraham Lincoln of Illinois and his running mate Senator Hannibal Hamlin of Maine. They defeated the Democratic nominee Senator Stephen A. Douglas of Illinois] and his running mate 41st Governor of Georgia Herschel V. Johnson. Lincoln won the state by a margin of 8.65%.

Results

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See also


References

  1. "1860 Presidential Election Results Indiana".

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