The 1860 United States presidential election in Iowa took place on November 6, 1860, as part of the 1860 United States presidential election. Iowa voters chose four representatives, or electors, to the Electoral College, who voted for president and vice president.

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1860 United States presidential election in Iowa

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Nominee Abraham Lincoln Stephen A. Douglas Party Republican Democratic Home state Illinois Illinois Running mate Hannibal Hamlin Herschel V. Johnson Electoral vote 4 0 Popular vote 70,302 55,639 Percentage 54.61% 43.22%

County Results Lincoln   40-50%   50-60%   60-70%   70-80%   80-90%   90-100% Douglas   40-50%   50-60%   60-70%   70-80%   80-90% Tie   ~50%

President before election James Buchanan Democratic Elected President Abraham Lincoln Republican

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Iowa was won by the Republican nominees Illinois Representative Abraham Lincoln and his running mate Senator Hannibal Hamlin of Maine. They defeated the Democratic nominees Senator Stephen A. Douglas of Illinois and his running mate 41st Governor of Georgia Herschel V. Johnson. Lincoln won the state by a margin of 11.39%.

• United States presidential elections in Iowa