1868_United_States_presidential_election_in_Georgia

1868 United States presidential election in Georgia

1868 United States presidential election in Georgia

Election in Georgia

The 1868 United States presidential election in Georgia took place on November 3, 1868, as part of the wider United States presidential election. Voters chose 9 representatives, or electors, to the Electoral College, who voted for president and vice president.

Main article: 1868 United States presidential election
Quick Facts Nominee, Party ...

The first readmission of Georgia to the Union occurred in 1868. The Seymour/Blair ticket carried the state of Georgia on election day. With 64.27% of the popular vote, Georgia would be Seymour's fourth strongest victory in terms of percentage in the popular vote after Kentucky, Louisiana and Maryland.[1]

Results

More information United States presidential election in Georgia, 1868, Party ...

References

  1. [1]
    "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  2. [2]
    Dave Leip’s U.S. Election Atlas; 1868 Presidential General Election Results – Georgia

Notes
    Share this article:

    This article uses material from the Wikipedia article 1868_United_States_presidential_election_in_Georgia, and is written by contributors. Text is available under a CC BY-SA 4.0 International License; additional terms may apply. Images, videos and audio are available under their respective licenses.