The 1884 United States presidential election in Alabama took place on November 4, 1884, as part of the nationwide presidential election. Alabama voters chose ten representatives, or electors, to the Electoral College, who voted for president and vice president.^[2]

Quick Facts Turnout, Nominee ...

1884 United States presidential election in Alabama

← 1880 November 4, 1884 1888 →
Turnout	12.03% of the total population 0.14 pp[1]
Nominee Grover Cleveland James G. Blaine Party Democratic Republican Home state New York Maine Running mate Thomas A. Hendricks John A. Logan Electoral vote 10 0 Popular vote 92,736 59,444 Percentage 60.37% 38.69%
County results Cleveland   50–60%   60–70%   70–80%   80–90%   90–100% Blaine   40–50%   50–60%   60–70%
President before election James A. Garfield Republican Elected President Grover Cleveland Democratic

Close

Alabama was won by Grover Cleveland, the 28th governor of New York, (D–New York), running with the former governor of Indiana Thomas A. Hendricks, with 60.37% of the popular vote, against Secretary of State James G. Blaine (R-Maine), running with Senator John A. Logan, with 38.69% of the vote.^[2]

• United States presidential elections in Alabama