The 1888 United States presidential election in Missouri took place on November 6, 1888, as part of the 1888 United States presidential election. Voters chose 16 representatives, or electors to the Electoral College, who voted for president and vice president.

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1888 United States presidential election in Missouri

← 1884 November 6, 1888 1892 →

Nominee Grover Cleveland Benjamin Harrison Party Democratic Republican Home state New York Indiana Running mate Allen G. Thurman Levi P. Morton Electoral vote 16 0 Popular vote 261,943 236,252 Percentage 50.24% 45.31%

County Results Cleveland   40-50%   50-60%   60-70%   70-80% Harrison   40-50%   50-60%   60-70%   70-80%

President before election Grover Cleveland Democratic Elected President Benjamin Harrison Republican

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Missouri voted for the Democratic nominee, incumbent President Grover Cleveland, over the Republican nominee, Benjamin Harrison. Cleveland won the state by a margin of 4.93%.

• United States presidential elections in Missouri