The 1892 United States presidential election in Minnesota took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Minnesota voters chose nine electors to the Electoral College, which selected the president and vice president.

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1892 United States presidential election in Minnesota

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Nominee Benjamin Harrison Grover Cleveland Party Republican Democratic Home state Indiana New York Running mate Whitelaw Reid Adlai Stevenson I Electoral vote 9 0 Popular vote 122,823 100,920 Percentage 45.96% 37.76%   Nominee James B. Weaver John Bidwell Party Fusion Prohibition Alliance Populist Home state Iowa California Running mate James G. Field James Cranfill Electoral vote 0 0 Popular vote 29,313 14,182 Percentage 10.97% 5.31%

County Results Harrison   30-40%   40-50%   50-60%   60-70%   70-80% Cleveland   30-40%   40-50%   50-60%   60-70% Weaver   30-40%   40-50%

President before election Benjamin Harrison Republican Elected President Grover Cleveland Democratic

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Minnesota was won by the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate Whitelaw Reid of New York.

The Minnesota Democratic Party initially announced that it would not conduct a fusion campaign, but later withdrew four of its electors in favor of Populist electors on October 10.^[1]

With 5.31 percent of the popular vote, Minnesota proved to be Prohibition Party candidate John Bidwell’s best performance as well as the only state where he broke 5 percent of the vote. This is the closest the Democrats came to winning Minnesota in the 19th century. ^[2]