1900_United_States_presidential_election_in_Wyoming

1900 United States presidential election in Wyoming

1900 United States presidential election in Wyoming

Election in Wyoming


The 1900 United States presidential election in Wyoming took place on November 6, 1900, as part of the 1900 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

Quick Facts Nominee, Party ...

Wyoming was won by the President William McKinley (ROhio), running with the 33rd Governor of New York, Theodore Roosevelt, with 58.66 percent of the popular vote, against representative William Jennings Bryan (DNebraska), running with the 23rd Vice President Adlai Stevenson I, with 41.17 percent of the popular vote.[1] McKinley won the state by a margin of 17.49%

McKinley had previously lost Wyoming to Bryan four years earlier while Bryan would later go on to lose the state again to William Howard Taft in 1908.

Results

More information Party, Candidate ...

Results by county

More information County, William McKinley Republican ...

Counties that flipped from Democratic to Republican

See also

Notes

  1. These "other" votes were tabulated only on a statewide basis and not separated by county.

References

  1. "1900 Presidential Election Results Wyoming".
  2. Robinson, Edgar Eugene; The Presidential Vote 1896-1932, pp. 377-379 ISBN 9780804716963

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