1948_United_States_presidential_election_in_Iowa

1948 United States presidential election in Iowa

1948 United States presidential election in Iowa

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The 1948 United States presidential election in Iowa took place on November 2, 1948, as part of the 1948 United States presidential election. Iowa voters chose ten[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Quick Facts All 10 Iowa votes to the Electoral College, Nominee ...

Iowa was won by incumbent Democratic President Harry S. Truman of neighbouring Missouri, running with Senator Alben W. Barkley, with 50.31% of the popular vote, against Governor Thomas Dewey (RNew York), running with Governor Earl Warren, with 47.58% of the popular vote.[3][4]

Results

More information Party, Candidate ...

Results by county

More information County, Harry S. TrumanDemocratic ...

See also


References

  1. "United States Presidential election of 1948 - Encyclopædia Britannica". Retrieved October 26, 2017.

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