2012_Swiss_Indoors_–_Doubles

2012 Swiss Indoors – Doubles

2012 Swiss Indoors – Doubles

2012 tennis event results


Michaël Llodra and Nenad Zimonjić were the defending champions but decided not to participate together.
Llodra was scheduled to play with Jérémy Chardy, but the pair withdrew before their first round match, while Zimonjić played alongside Daniel Nestor and successfully defended the title, defeating Treat Conrad Huey and Dominic Inglot 7–5, 6–7(4–7), [10–5] in the final.

Quick Facts Doubles, Final ...

Seeds

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Canada D Nestor
Serbia N Zimonjić
6 6  
WC Switzerland M Chiudinelli
Switzerland M Lammer
0 4   1 Canada D Nestor
Serbia N Zimonjić
77 6  
  Poland Ł Kubot
Italy A Seppi
6 6     Poland Ł Kubot
Italy A Seppi
62 4  
  Austria O Marach
Germany F Mayer
4 3   1 Canada D Nestor
Serbia N Zimonjić
6 6  
3 Pakistan A-u-H Qureshi
Netherlands J-J Rojer
4 77 [6]   Italy D Bracciali
Czech Republic F Čermák
3 4  
  Italy D Bracciali
Czech Republic F Čermák
6 65 [10]   Italy D Bracciali
Czech Republic F Čermák
5 7 [10]
WC Switzerland A Bossel
Switzerland H Laaksonen
2 2     South Africa K Anderson
Serbia V Troicki
7 5 [5]
  South Africa K Anderson
Serbia V Troicki
6 6   1 Canada D Nestor
Serbia N Zimonjić
7 64 [10]
  United Kingdom J Marray
Denmark F Nielsen
78 2 [10]   Philippines TC Huey
United Kingdom D Inglot
5 77 [5]
  United States E Butorac
Australia P Hanley
66 6 [5]   United Kingdom J Marray
Denmark F Nielsen
5 66  
  France J Benneteau
France R Gasquet
77 4 [10] 4 Poland M Fyrstenberg
Poland M Matkowski
7 78  
4 Poland M Fyrstenberg
Poland M Matkowski
65 6 [12] 4 Poland M Fyrstenberg
Poland M Matkowski
65 5  
  Philippines TC Huey
United Kingdom D Inglot
6 7     Philippines TC Huey
United Kingdom D Inglot
77 7  
  Brazil T Bellucci
Finland J Nieminen
2 5     Philippines TC Huey
United Kingdom D Inglot
77 6  
Alt Netherlands R Haase
Belgium D Norman
7 2 [14] Alt Netherlands R Haase
Belgium D Norman
65 4  
2 India M Bhupathi
India R Bopanna
5 6 [12]

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