Fife_Lake,_Saskatchewan

Fife Lake, Saskatchewan

Fife Lake, Saskatchewan

Add article description

For other uses, see Fife Lake (disambiguation).

Fife Lake[1] is a hamlet located between Coronach and Rockglen within Rural Municipality of Poplar Valley No. 12 in south-central Saskatchewan, Canada near the border with the United States. Approximately 40 people inhabited the village of Fife Lake in 2006. It is about 11 kilometres (6.8 mi) east of Rockin Beach Park and Fife Lake.[2]

Fife Lake
Fife Lake
Location of Fife Lake in Saskatchewan

History

Prior to January 27, 2005, Fife Lake was incorporated as a village, and was restructured as a hamlet under the jurisdiction of the RM of Poplar Valley on that date.[3]

Demographics

In the 2021 Census of Population conducted by Statistics Canada, Fife Lake had a population of 25 living in 17 of its 23 total private dwellings, a change of 0% from its 2016 population of 25. With a land area of 0.36 km2 (0.14 sq mi), it had a population density of 69.4/km2 (179.9/sq mi) in 2021.[4]

See also

References

  1. [1]
    "Fife Lake". Canadian Geographical Names Database. Government of Canada. Retrieved January 7, 2023.
  2. [2]
    "Rockin Beach Park". Tourism Saskatchewan. Government of Saskatchewan. Retrieved January 7, 2023.
  3. [3]
    "Restructured Villages". Saskatchewan Ministry of Municipal Affairs. Archived from the original on March 25, 2008. Retrieved February 10, 2008.
  4. [4]
    "Population and dwelling counts: Canada and designated places". Statistics Canada. February 9, 2022. Retrieved August 31, 2022.

49°11′39″N 105°43′52″W


Stub icon

This article about a location in the Census Division No. 3 of Saskatchewan is a stub. You can help Wikipedia by expanding it.
Share this article:

This article uses material from the Wikipedia article Fife_Lake,_Saskatchewan, and is written by contributors. Text is available under a CC BY-SA 4.0 International License; additional terms may apply. Images, videos and audio are available under their respective licenses.