United_States_presidential_election_in_Washington,_1996

1996 United States presidential election in Washington (state)

1996 United States presidential election in Washington (state)

Add article description


The 1996 United States presidential election in Washington took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for president and vice president.

Quick Facts Turnout, Nominee ...

The State of Washington was won by President Bill Clinton (DAR) over Senator Bob Dole (RKS), with Clinton winning 49.84% to 37.30% for a margin of 12.54%. Billionaire businessman Ross Perot (ReformTX) finished in third, with 8.92% of the popular vote.[2] As of the 2020 presidential election, this is the last election in which Spokane County, Kittitas County, Pend Oreille County, Ferry County, and Asotin County voted for a Democratic presidential candidate.[3]

Results

More information Party, Candidate ...

Results by county

More information County, Bill Clinton Democratic ...

Counties that flipped from Democratic to Republican

See also


References

  1. Secretary of State: Kim Wyman. "Voter Turnout by Election". www.sos.wa.gov. Retrieved May 25, 2020.
  2. Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016
  3. "Elections Search Results - November 1996 General". Washington Secretary of State. Retrieved June 24, 2022.

Share this article:

This article uses material from the Wikipedia article United_States_presidential_election_in_Washington,_1996, and is written by contributors. Text is available under a CC BY-SA 4.0 International License; additional terms may apply. Images, videos and audio are available under their respective licenses.