United_States_presidential_election_in_Wisconsin,_1988

1988 United States presidential election in Wisconsin

1988 United States presidential election in Wisconsin

Election in Wisconsin


The 1988 United States presidential election in Wisconsin took place on November 8, 1988. All 50 states and the District of Columbia, were part of the 1988 United States presidential election. State voters chose 11 electors to the Electoral College, which selected the president and vice president.

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Wisconsin was won by Massachusetts Governor Michael Dukakis who was running against incumbent United States Vice President George H. W. Bush of Texas. Dukakis ran with Texas Senator Lloyd Bentsen as Vice President, and Bush ran with Indiana Senator Dan Quayle. Dukakis won the election in Wisconsin with a four point margin. The state has since consistently voted for the Democratic Party, until the narrow victory of Republican Donald Trump in 2016.

The election was very partisan, with over 99 percent of the electorate voting for either the Republican or Democratic parties, although five additional candidates were on the ballot.[1] Dukakis and Bush almost evenly split Wisconsin's seventy-two counties – Dukakis won 37 and Bush won 35. Dukakis won the large urban counties containing Madison (Dane County), Milwaukee, Racine and Kenosha, alongside almost entirely Native American Menominee County and the heavily unionized Scandinavian-American counties of the northwest. Bush won the suburban "WOW counties" and the more conservative, historically German Catholic, counties of the rural eastern half of the state.[2] Over the state as a whole, Dukakis did best, as usual, in Menominee County, and Bush did best in Ozaukee County.

Results

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Results by county

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Counties that flipped from Republican to Democratic

Analysis

Wisconsin weighed in for this election as 12 points more Democratic than the national average. As of 2020, this is the last election in which Green County voted for a Republican presidential candidate,[4] and the last time that the state would vote to the left of neighboring Michigan or Illinois. This would be the most recent election when the Democratic candidate won Wisconsin while losing Illinois at the same time, and the last time they voted differently until 2016.

It was also the first time since 1960 that Wisconsin would back the losing candidate in a presidential election.[5] It was also the first time since 1848 that the state would back a losing Democrat in a presidential election, and the first time ever that the state would back a Democrat while a Republican won the presidency. This was the first time since 1924 that a Republican won without the state.

See also

Notes

  1. Votes for this candidate were not separated by county but listed only as a statewide total.[3]

References

  1. "1988 Presidential General Election Results – Wisconsin". Dave Leip's Atlas of U.S. Presidential Elections. Retrieved July 21, 2013.
  2. Phillips, Kevin P.; The Emerging Republican Majority, pp. 381-382, 414 ISBN 978-0-691-16324-6
  3. Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016

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