1940_United_States_presidential_election_in_Kansas

1940 United States presidential election in Kansas

1940 United States presidential election in Kansas

Election in Kansas


The 1940 United States presidential election in Kansas took place on November 5, 1940, as part of the 1940 United States presidential election. Voters chose nine[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Quick Facts All 9 Kansas votes to the Electoral College, Nominee ...

Kansas was won by Wendell Willkie (RNew York), running with Minority Leader Charles L. McNary, with 56.86 percent of the popular vote, against incumbent President Franklin D. Roosevelt (DNew York), running with Secretary Henry A. Wallace, with 42.40 percent of the popular vote.[3][4] This was the first time since 1896 that Kansas voted for a losing candidate, and the first time since 1884 that the state backed a losing Republican in a presidential election.

With 56.86 percent of the popular vote, Kansas would prove to be Willkie's third strongest state in the 1940 election in terms of popular vote percentage after South Dakota and neighboring Nebraska.[5]

Results

More information Party, Candidate ...

Results by county

More information County, Wendell Lewis Willkie Republican ...

See also


References

  1. "United States Presidential election of 1940 — Encyclopædia Britannica". Retrieved August 19, 2018.
  2. "1940 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
  3. Scammon, Richard M. (compiler); America at the Polls: A Handbook of Presidential Election Statistics 1920-1964; pp. 167-168 ISBN 0405077114

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