The 1988 United States presidential election in the District of Columbia took place on November 8, 1988, as part of the 1988 United States presidential election. Voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.

This article relies largely or entirely on a single source. (April 2016)

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1988 United States presidential election in the District of Columbia

← 1984 November 8, 1988 1992 →

Nominee Michael Dukakis George H. W. Bush Party Democratic Republican Home state Massachusetts Texas Running mate Lloyd Bentsen Dan Quayle Electoral vote 3 0 Popular vote 159,407 27,590 Percentage 82.65% 14.30%

Ward Results Dukakis   60-70%   70-80%   80-90%   90-100%

President before election Ronald Reagan Republican Elected President George H. W. Bush Republican

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Washington, D.C. overwhelmingly voted for Governor Michael Dukakis of Massachusetts, the Democratic candidate. Vice President George H. W. Bush received 14.3% of the vote. This is the most recent election in which the Republican candidate received more than 10% of the vote in the District of Columbia, and it was one of only two areas that leaned more Republican than in the presidential election of 1984, which had resulted in a Republican landslide, the other being Tennessee.

• United States presidential elections in the District of Columbia