Quasimomentum.gif


Summary

Description
English: Since you can draw an infinite different sinusoidals through the same set of periodically spaced oscillators, you can not unequivocally define a k-vector, and thus a momentum. A didactic animation.
Date
Source https://twitter.com/j_bertolotti/status/1060532687436431362
Author Jacopo Bertolotti
Permission
( Reusing this file )
https://twitter.com/j_bertolotti/status/1030470604418428929

Mathematica 11.0 code

p1 = Table[
   Show[
    Plot[Cos[x] Sin[t], {x, 0, 9}, 
     PlotStyle -> {Gray, Thick, Opacity[(Erf[t - 6.5] + 1)/2]}, 
     PlotRange -> {-1.1, 1.1}, Axes -> False]
    ,
    Plot[Cos[(1 + (2 \[Pi])/a) (x)] Sin[t], {x, 0, 9}, 
     PlotStyle -> {Purple, Thick, Opacity[(Erf[t - 13] + 1)/2]}]
    ,
    Plot[Cos[(1 + 2 (2 \[Pi])/a) (x)] Sin[t], {x, 0, 9}, 
     PlotStyle -> {Orange, Thick, Opacity[(Erf[t - 18.5] + 1)/2]}]
    ,
    Graphics[{PointSize[0.03], Point[p[t] ]} ]
    , PlotPoints -> 100
    ]
   , {t, 0, 25, 0.1}];
ListAnimate[p1, 10]

Licensing

I, the copyright holder of this work, hereby publish it under the following license:
Creative Commons CC-Zero This file is made available under the Creative Commons CC0 1.0 Universal Public Domain Dedication .
The person who associated a work with this deed has dedicated the work to the public domain by waiving all of their rights to the work worldwide under copyright law, including all related and neighboring rights, to the extent allowed by law. You can copy, modify, distribute and perform the work, even for commercial purposes, all without asking permission.


This image, originally posted to Flickr , was reviewed on 7 April 2019 by the administrator or reviewer Ronhjones , who confirmed that it was available on Flickr under the stated license on that date.

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8 November 2018

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